Webb6 okt. 2024 · We now draw a line through the point P(−2, 2) that is parallel to the line through the points Q and R. Parallel lines must have the same slope, so we start at the point P(−2, 2), “run” 5 units to the right, then “rise” 2 units up to the point T(3, 4), as shown in Figure \(\PageIndex{4}\)(b). WebbSo the equation for PQ is y = 2 /*3*x +... So the slope of QR will be the negative inverse of that = -3 /2. The equation for line QR is y = -3 /*2*x + b . where b is the y-intercept. Using …
Circle Question : r/cheatatmathhomework
WebbFigure 2 The points P(−3, 2), Q(9, 10) and R(a, 4) lie on the circle C, as shown in Figure 2. Given that PR is a diameter of C, (a) show that a = 13, (3) (b) find an equation for C. (5) … Webb14 juli 2024 · Parameterize the line through P= (−3,−1) and Q= (0,7) so that the points P and Q correspond to the parameter values t=13 and 16. I have found the direction vector <3,8> and then have plugged in to find the following: r=<-3,-1> +t<3,8> x=3t-3 y=8t-1 I am lost as to the next steps to scale this appropriately to come up with the correct equation. datong jinsheng haoda coal industry co. ltd
Examples of collinear points Collinearity) - BYJUS
WebbMath Geometry QUESTION 4 The points P (-3: 2), Q (9: 10) and R (a, 4) lie on the crcumference of t circle, as shownm in the figure below. PR is a diameter of the circle … WebbExample 1: Find the value of a, if the distance between the points P (3, -6) and Q (-3, a) is 10 units. Solution: Let the given points be: P (3, -6) = (x 1, y 1) Q (-3, a) = (x 2, y 2) Using distance formula, Distance between the points P (3, -6) and Q (-3, a) is: [(-3 – 3)2 + (a + 6)2] = 10 units (given) Squaring on both sides of the equation, Webb125 Likes, 3 Comments - Alisa (@alisa_saves_with_coupons) on Instagram: "CVS HAUL (8/9-8/15) Feel Free to ask any questions about coupons and crts I used *Colga ... daton fix high school